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Explicitly define copy assignment operator 

The implicit copy assignment operator was deprecated because the class
has an explicit copy constructor. According to the standard:

The generation of the implicitly-defined copy assignment operator is
deprecated (since C++11) if T has a user-declared destructor or
user-declared copy constructor.

Recent versions of gcc (9.1+) and clang (10.0) warn about this.
This commit is contained in:
Martijn Otto 2020-01-28 14:59:55 +01:00
parent 8eedc8a390
commit 5002a0343f
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7
contrib/epee/include/storages/portable_storage_base.h
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@ -84,6 +84,13 @@ namespace epee
array_entry_t():m_it(m_array.end()){} array_entry_t():m_it(m_array.end()){}
array_entry_t(const array_entry_t& other):m_array(other.m_array), m_it(m_array.end()){} array_entry_t(const array_entry_t& other):m_array(other.m_array), m_it(m_array.end()){}
array_entry_t& operator=(const array_entry_t& other)
{
m_array = other.m_array;
m_it = m_array.end();
return *this;
}
const t_entry_type* get_first_val() const const t_entry_type* get_first_val() const
{ {
m_it = m_array.begin(); m_it = m_array.begin();