Explicitly define copy assignment operator
The implicit copy assignment operator was deprecated because the class has an explicit copy constructor. According to the standard: The generation of the implicitly-defined copy assignment operator is deprecated (since C++11) if T has a user-declared destructor or user-declared copy constructor. Recent versions of gcc (9.1+) and clang (10.0) warn about this.
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@ -84,6 +84,13 @@ namespace epee
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array_entry_t():m_it(m_array.end()){}
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array_entry_t(const array_entry_t& other):m_array(other.m_array), m_it(m_array.end()){}
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array_entry_t& operator=(const array_entry_t& other)
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{
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m_array = other.m_array;
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m_it = m_array.end();
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return *this;
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}
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const t_entry_type* get_first_val() const
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{
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m_it = m_array.begin();
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